I have to find the zeros of a function, the funtion being
f(x) = x^4 - 3(X)^2 + 2

This is what I could figure out.

The possible number of positive zeros is 2 or 0, and the possible number of negative zeros is 2 or 0, because of Descart's Rule of Signs.

This is the part I think I might be messing up, where you take the "p", which is the the coeffeicient of the highest degree, and the "q" which is the coefficient of the lowest degree.  So I figure P is 1 and Q is 2.

Now I take the facotrs of 1 which are (+ or -) 1 and the factors of 2 which are (+ or -) 1 and 2.

Then I figure that the possible zeros are all the posssible (P/Q)'s. So that would be (+1, -1, +(1/2) and -(1/2).  After graphin the equation 2 of the zeros are 1 and -1, while the other 2 seem to be 1.4....  So I'm not sure what I'm doing wrong.  Any ideas???