Physics education research, electronic materials, and the musings of Christopher Moore, Ph.D.
Physics education research, electronic materials, and the musings of Christopher Moore, Ph.D.
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A 91.2-N ladder is in equilibrium, resting on two sawhorses. One is 1.00 m from the center of mass, the other is 0.50 m from the center of mass. What is the force each sawhorse exerts on the ladder?
I know that for equilibrium, the net torque and net force are supposed to equal zero but I can't remember how to set it up?
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∑T(Torque) = 0
x = force for sawhorse 1
y = force for sawhorse 2
-(x * 1m) + (y * 0.5m) = 0
∑F = 0
x + y = 91.2,
So
-x + 0.5y = 0
x + y = 91.2
________________+
1.5y = 91.2
y = 60.8 Newton and x = 30.4 Newton
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