Physics education research, electronic materials, and the musings of Christopher Moore, Ph.D.

1) reaction at A:
    force 1: 20kN/m . 6 m = 120 kN, if I using point mass approximation, it will be act at 3 meter above                  point A. Because force 1, not at point A, it will be torsion in there. That is 120kN . 3 m = 360  kNm
    force 2: 60kN at point C, 4 meter beside point A. Because force 2, not at point A, it will be torsion in there. That is 60kN . 3 m = 180  kNm
    force 3: 30kN/m . 7 m = 210 kN at point D because that's hinge. Because force 3, not at point A, it will be torsion in there. That is 210kN . 11 m = 2310  kNm.
Let's add this 3 torsion, 360 + 180 + 2310= 2850 kNm. And point A will be suffer torsion in clockwise direction with scale 2850 k.
For other question. You can be answer yourself after you read my answer.

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