Physics education research, electronic materials, and the musings of Christopher Moore, Ph.D.

yurisaku · 2010-09-17 08:45:42

calculate the integral
integral Dirac delta square (x^2 - a^2) x^2 dx
where a > 0 and Dirac delta is the Dirac delta function.

panku32 · 2012-03-24 15:50:41

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panku32 · 2012-03-24 15:51:59

This is a great post. I like this post. Thanks for sharing this post.

Neo · 2012-04-17 20:10:12

yurisaku wrote:
calculate the integral
integral Dirac delta square (x^2 - a^2) x^2 dx
where a > 0 and Dirac delta is the Dirac delta function.

Is this a question for your homework? I'll, try and lead you on the right direction.

You notice this part?

$(x^2 - \alpha^2)$

The function usually is seen as

$\delta(x^2 - \alpha^2)$

and you can rewrite this as

$\delta(x + \alpha) + (x - \alpha)$

Your integral should be then

$f(\alpha) = \int_{-\infty}^{\infty} \delta(x + \alpha) + (x - \alpha) x^2 dx$

This should lead you in the right direction at least.

Last edited by Neo (2012-04-17 20:12:12)

Physics education research, electronic materials, and the musings of Christopher Moore, Ph.D.

#1 2010-09-17 08:45:42

calculate the integra, Dirac delta function

#2 2012-03-24 15:50:41

Re: calculate the integra, Dirac delta function

#3 2012-03-24 15:51:59

Re: calculate the integra, Dirac delta function

#4 2012-04-17 20:10:12

Re: calculate the integra, Dirac delta function

yurisaku wrote:

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