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I have been having serious problems with this physics question on one of my assignments. I know the answer is 0.14 J, but I have no idea how to get there. I think you have to use the formula F=kx or Ep= 1/2kxsquared but I am not positive.
a spring having a constant of 44 N/m is initially compressed 4.0cm. It is then compressed another 5.0cm in a time of 1.4s. Determine the work done to compress the spring from 4.0 cm to 9.0 cm.
Thanks for any help!
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Potential energy stored in the spring during 4.0 cm compression W1 = 0.5*44*(4x10^-2)^2
Potential energy stored in the spring during 9.0 cm compression W2 = 0.5*44*(9x10^-2)^2
So the work done to compress the spring from 4.0 cm to 9.0 cm is (W2 - W1)
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