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shashank · 2005-09-11 11:00:05

Hey guys....

Here's a good one....

There is a beaker full of water uptil a depth of 80cm. Now there is a bulb placed at the bottom of the beaker (within the water).
Now, what you all have to calculate is the amount of surface the bulb will take when it emerges out of the water - beaker prepndicularly.
(Given that the Refractive index of water is 4/3)

Shashank

Chris · 2005-09-11 22:51:12

I'm confused by your wording. The bulb emits light, correct? Do you mean the area on the water surface that the emitted beam passes through?

Are we to assume a point source, or does the bulb have some physical diameter and height? Also, can we assume the bulb is in the center of the beaker?

shashank · 2005-09-12 17:14:20

Actually there's no need for assuming that bulb in the center thing....

You are to assume it as a point source and then solve....

The bulb doesn't emit light.... it is just placed at the bottom of the beaker

Shashank

Chris · 2005-09-12 18:08:05

You are to assume it as a point source and then solve....

The bulb doesn't emit light.... it is just placed at the bottom of the beaker

But if it doesn't emit light, then how is it a point source of light? What you are asking, then, is if I draw a dot with negligible diameter on the bottom of the beaker, how big does the dot appear from outside the water?

shashank · 2005-09-15 18:32:16

It's not that.......

Basically there's a bulb with a definite diameter but, solve it as by taknig it as a dot emitting light........

(Use sin ic )

Announcement

#1 2005-09-11 11:00:05

Refraction - Light

#2 2005-09-11 22:51:12

Re: Refraction - Light

#3 2005-09-12 17:14:20

Re: Refraction - Light

#4 2005-09-12 18:08:05

Re: Refraction - Light

#5 2005-09-15 18:32:16

Re: Refraction - Light

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