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Hi, Im working on the following question.
A 64 µC charge is located 30cm to the left of a 16 µC charge. What is the resultant force on a -12 µC charge positioned exactly 50mm below the 16 µC charge?
I set it up like this.
a .3m b
64 µC ---------------------------16 µC
i
i
i .05m
i
-12 µC
c
So I tried to solve using the vector components as follows
Fac=9.0e9(65x10e-6 * 12x10e-6)/(.3^2+.05^2) = 74.72C
Fbc = 9.0e9(16x10e-6 * 12x10e-6)/(.05^2) = 691.2C
I'm not sure where to go from here...I've tried to solve is a number of times but cant get the correct answer. I think when i set the problem up to solve for the vectors I'm doing it wrong.
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Angle bac = arctan(0.05/0.3) = 9.3 degrees.
Resultant force Fr = sqrt[ (Fac)^2 + (Fbc)^2 + 2*Fac*Fbc*cos(9.3)]
Substitute the values and find the resultant.
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