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Gday,
Just having a problem doing the initial rearrangement, before I integrate it, of the following differential equation to get the y's and x's on the same side:
(x^{2}+1)y' = xy
Can anyone help me out with this? Ive been trying all day to get both x and y on either side but I cant manage. Is there a trick to it?
Any help appreciated!
Thanks
Matthew
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(x^{2}+1)y' = xy
rewrite the above equation as
dy/y = xdx/(1+x^2)
and integrate both the sides.
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