Physics education research, electronic materials, and the musings of Christopher Moore, Ph.D.
Physics education research, electronic materials, and the musings of Christopher Moore, Ph.D.
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If the two lenses in the figure are separated by 11.0 cm, locate the final image and find the magnification of the system. [Hint: The object for the second lens is virtual!]
q = ?
(Remember that a multiple lens system is a series of single lens systems with the image of one lens acting as the object for the next lens in line.) cm
M = ?
(To find the total magnification of a multiple lens system, multiply together the magnification caused by each of the individual lenses. )
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i tried but i couldn't, sorry..
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If the two lenses are seperated by 11 cm,
for the first lens
u=-30
f1=10
we have, 1/v-1/u=1/f
so the final image from 1st lens will be at 15 cms ,i.e 15 cms rifht of 1st lens, hence 4 cms right of 2nd lens.
So for 2nd lens, we have u=+4
f2=20
again using , 1/v-1/u=1/f; we have v=3.33 cm right of 2nd lens.
and magnification=magnification for first lens* that for 2nd lens=15/(-30) * 3.33/4= - .41
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