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TOPanic · 2008-03-01 20:29:20

I am trying to calulcate the mass of a box. I do not know the dimensions of the box. All I was given for my problem was that it takes 398N to push the box constantly up an incline of 29.74 degrees off horizontal(force applied).

the incline plane is 8.06 meters in length.

I was not given mass or mu and I am expected to find Fp, Fn, A, t, Vf.

Do you think that you can help me with this?

Thanks for your assistance.

K.

boesmanprinses · 2008-03-27 18:06:42

If we accept that there is no friction on this plane, the answer is actually very easy.
We know that the incline is 29,74 deg. And it takes 398N to push the box constantly up the incline. The word CONSTANT tells us that the forces working on the box is in equilibrium

Now we can take the 398N and brake it down into a vertical force and a Horizontal force, by using some trigonometry.

Sin29,74 = _t_
398N

398sin29.74 = t

t = 197.43N (this is the downwards force, caused by the weight of the box and gravety)

Mass x 10 = newton
Mass of the box = 19.743Kg

Excuse the spelling and grammar, english is not myt first language

Hope i could help

Gerhard

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#1 2008-03-01 20:29:20

two dimensional inclined plane calculation

#2 2008-03-27 18:06:42

Re: two dimensional inclined plane calculation

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