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#1 2008-02-28 19:28:51

dovix85
New Member
Registered: 2008-02-28
Posts: 4

Space and Time - Motion

heres a good one..I was looking through work I did for a course at the Natural History in NYC.
Anyone know the answer to this?

Let investigate a space vacation. Your spaceship, which has a proper length of 300 m, passes near a space platform while you are moving at a relative speed of 0.86 c. What is the length of the spaceship when measured by someone on the space platform? What is the length of the spaceship from your perspective in the spaceship? The length is, of course, different from these two frames of reference. Does the length really change?

You can use the following equation:

Equation for length contraction
L = L' * √ (1 - v2/c2)

Where:
L = The length of the spaceship as seen by the observer
L' = The proper length of the spaceship
v = The velocity of the spaceship
c = The speed of light.

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#2 2008-02-29 07:59:08

Martin
Moderator
From: Earth
Registered: 2004-10-04
Posts: 367

Re: Space and Time - Motion

dovix85 wrote:

....The length is, of course, different from these two frames of reference. Does the length really change?

Change? From what to what? As you pointed out, the two observers will obtain different values for the length. But nothing "changes." The lengths, though they differ, are equally "real" (in every sense of the word) to their respective observers.


The truth is out there.

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#3 2008-02-29 14:23:07

dovix85
New Member
Registered: 2008-02-28
Posts: 4

Re: Space and Time - Motion

Looking for the equation/formulat to do it.

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#4 2008-02-29 16:44:39

Martin
Moderator
From: Earth
Registered: 2004-10-04
Posts: 367

Re: Space and Time - Motion

dovix85 wrote:

Looking for the equation/formulat to do it.

To do what??


The truth is out there.

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