The total energy of a particle with mass m, momentum p, and potential energy V can be written as

But in quantum mechanics p is no longer the momentum, but becomes the momentum operator. I won't go into the math details of this operator but just keep in mind that the p^2/2m term only resembles kinetic energy. So when the above equation is used in quantum mechanics, it only resembles total energy E. The momentum operator OPERATES on a wavefunction Psi (greek letter Psi). The wavefunction only represents the probability distribution of finding a particle with a certain energy. Schrodingers Equation calls the left side of the above equation H, and says

Since Psi is a probability distribution is why I say that the H in Schrodingers equation only resembles energy. H is composed of operators, so guess what. H is an operator. H operates on a wavefunction Psi, and the result is the energy E which is what you measure in the lab.
So to answer your question, schrodingers equation is used to find the energy of, for example, an electon. By the way, theres not really a connection per se between schrodingers equation and the uncertainty principle, at least not that I'm aware of.
Last edited by jason_c (2005-03-24 00:32:20)
The OG (Original Gauss' Law)