Here is my problem: 

A ball is thown at a wall at a speed of 33.0m/s and at an angle of 37 degrees above horizontal, with the wall distance being 20 m from the release point.  How far above the release point does the ball it the wall?

I assume I am solving the displacement on the Y axis and this is what I have so far...

The initial velocity upwards would be 33(sin37)=20 m/s
The horizontal component would be 33(cos 37)=26 m/s

Vfy=Viy + Ay Delta time
0=20m/s-9.80(delta time)
T=20/9.8=2.04 seconds

***I'm not sure if I'm doing this right and this is where I'm stuck...Any help would be greatly appreciated!!

Last edited by johnsoda (2007-10-16 21:18:38)